For best view of this site use Google Chrome

Advertisement

Popular Posts

Services

Thermodynamics - India Study Solution Test Series, Chemistry objective questions for NEET, JEE Main other entrance exams

 

THERMODYNAMICS

Chemistry India Study Solution Test Series (Confidence Booster)
NEET, JEE Main, JEE Advanced, IIT, AIIMS, NTSE | MBBS, BDS Admission Test
https://www.indiastudysolution.com - graphics
Welcome guys to your own site India Study Solution
Below you will get carefully selected, 10 MCQ practice questions in our each Test Series with hints & solutions (given at the end) from our Chemistry Solutions exclusively from - Thermodynamics, Thermo Chemistry.
Each series or set is a combination of 10 typically important some basic and also advanced level questions for NEET-UG, JEE Main & Advanced (IIT) AIIMS, IMS BHU, JIPMER, COMEDK, MBBS Admission Tests, Engineering Entrance Exams, NEST and other such competitive exams.
Please scroll down for NEET and JEE syllabus of Thermodynamics chapter.


Chemistry Practice Questions: Thermodynamics (Thermo chemistry)
MCQ Test Series – Set 2 (Q. No 11-20)
Question 11: A process in which no heat change takes place is called
a. An isothermal process
b. An adiabatic process
c. An isobaric process
d. An isochoric process 

Question 12: When a solid melts there is
a. An increase in enthalpy
b. A decrease in enthalpy
c. No change in enthalpy
d. A decrease in internal energy

Question 13: The change in enthalpy that takes place when one mole of the compound is formed from its elements is called
a. Heat of formation
b. Heat of fusion
c. Heat of combustion
d. Heat of sublimation

Question 14: Hess’s law states that
a. The standard enthalpy of an overall reaction is the sum of the enthalpy changes in individual reaction
b. Enthalpy of formation of compound is same as the enthalpy of decomposition of the compound into constituent elements, but with opposite sign
c. At constant temperature the pressure of a gas is inversely proportional to its volume
d. The mass of a gas dissolved per lit of a solvent is proportional to the pressure of the gas in equilibrium with the solution

Question 15: Hess’s law is used to determine
a. Heat of formation of substances which are otherwise difficult to calculate
b. Heat of transition
c. Heat of dissociation
d. All of these

Question 16: A certain mass of gas is expanded from (1L, 10 atm) to (4L, 5 atm) against a constant external pressure of 1 atm. If initial temperature of gas is 300K and the heat capacity of process is 50 J/oC. Then the enthalpy change during the process is (1 L ~ 100 J)
a. ∆H = 15 kJ
b. ∆H = 15.7 kJ
c. ∆H = 14.4 kJ
d. ∆H = 14.7 kJ

Question 17: The enthalpies of elements under the following conditions are assumed to be
a. Zero at 298K and 1 atm
b. Unity at 298K and 1 atm
c. Zero at 273K and 1 atm
d. Unity at 273K and 1 atm

Question 18: If the total enthalpy of reactants and products is HR and HP respectively, then for exothermic reaction
a. HR = HP
b. HR < HP
c. HR > HP
d. HP ≥ HR

Question 19: The first law of thermodynamics is represented by the equation:
a. ∆E = Q - W
b. ∆E = Q + W
c. W = Q + ∆E
d. Q = W + ∆E

Question 20: Enthalpy of neutralisation of all strong acids and strong bases has the same value because
a. Neutralisation leads to the formation of a salt and water
b. Strong acid and bases are iconic substances
c. Acids always furnish H+ ions and bases always furnish OH- ions
d. The net chemical change involves the combination of 1 mol of H+ ions and 1 mol OH- ions to form water.
Thermodynamics (Syllabus for NEET and JEE):
Fundamentals of thermodynamics: System and surroundings, extensive and intensive properties, state functions, types of processes. Thermal equilibrium, Zeroth law of thermodynamics, concept of temperature. First  law  of  thermodynamics: internal  energy  and  enthalpy,  heat  capacity  and  specific  heat, measurement of U and H, Hess’s law of constant heat summation. Enthalpies of bond dissociation, combustion, formation, atomization, sublimation, phase transition, ionization, solution and dilution. Introduction of entropy as state function. Second law of thermodynamics: Gibbs energy change for spontaneous and non-spontaneous processes, reversible and irreversible processes, criteria for equilibrium and spontaneity. Carnot engine and its efficiency. Third law of thermodynamics: Brief introduction.
India Study Solution - Hints and Solutions Chemistry MCQ Test Series
Thermodynamics
Solutions of Chemistry Test Series (MCQ) – Set 2 (Q. No.11–20)
Answer 11: b. Answer 12: a. Answer 13: a. Answer 14: a. Answer 15: d.
Answer 16: b.
Hint:
H = E + (PV) and
∆E = q + W = (50 x 300 – 3 x 100) J [as Tf = 2 x 300 K = 600 K] = 14.7 kJ
∆H = 14700 + 10 x 100 = 15700 J = 15.7 kJ
Answer 17: a. Answer 18: c. Answer 19: b. Answer 20: d.

 THERMODYNAMICS - India Study Solution Chemistry Test Series Questions

<< Previous (Q.No. 1-10)           (Q.No. 21-30) Next >>

0 on: "Thermodynamics - India Study Solution Test Series, Chemistry objective questions for NEET, JEE Main other entrance exams "