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NEET and JEE preparation | Physics Guide with Hints and Solutions | Electrostatics

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 Electrostatics

India Study Solution MCQ Test Series

(Practice Questions with Hints and Solutions)

NEET, JEE Main, JEE Advanced | Medical and Engineering Entrance Exams | MBBS Admission Test

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Here is your next Test Series a set of 10 most important solved questions (Q. No. 21-30) for NEET and JEE from Electrostatics in Physics with their hints & solutions.

Click to check NEET and JEE Main Syllabus for chapter Electrostatics.

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So, friends without wasting further time let us start -

Electrostatics  - Questions Bank with Solutions

India Study Solution Test Series – Set 3 (Q. No 21-30)

Question 21: When charge is given to a body

a. more charge accumulates at regions of small curvature

b. more charge accumulates at regions of large curvature

c. charge is distributed uniformly irrespective of curvature

d. none of the above is true

 

Question 22: Two equal positive charges are kept at points A and B. The electric potential at the points between A and B (excluding these points) is studied while moving from A to B. The potential

a. continuously increases

b. continuously decreases

c. increases then decreases

d. decreases then increases

 

Question 23: There are two metallic spheres of same radii but one is solid and the other is hollow, then:

a. solid sphere can be given more charge

b. hollow sphere can be given more charge

c. they can be charged equally (maximum)

d. none of the above

 

Question 24: A charge of 5C experiences a force of 5000N when it is kept in uniform electric field. What is the potential difference between two points separated by a distance of 1cm?

a. 10V

b. 250V

c. 1000V

d. 2500V

 

Question 25: The unit of permittivity of free space εo is

a. coulomb/newton-metre

b. coulomb2/newton-metre2

c. newton-metre2/coulomb2

d. coulomb2/(newton-metre)2

 

Question 26: The electric charge in uniform motion produces-

a. an electric field only

b. a magnetic field only

c. both electric and magnetic fields

d. neither electric nor magnetic fields

 

Question 27: A conductor has 14.4 x 10-19 C positive charge. The conductor has:

(Charge on electron = 1.6 x 10-19 C)

a. 9 electrons in excess

b. 27 electrons in short

c. 27 electrons in excess

d. 9 electrons in short

 

Question 28: An electric dipole is placed in a uniform electric field. The net electric force on the dipole

a. is always zero

b. depends on the orientation of the dipole

c. can never be zero

d. depends on the strength of the dipole

 

Question 29: A charged particle (charge q) is moving in a circle of radius R with uniform speed v. The associated magnetic moment μ is given by:

a. qvR/2

b. qvR2

c. qvr2/2

d. qvR


Question 30: The law, governing the force between electric charges is known as

a. Ampere’s law

b. Ohm’s law

c. Faraday’s law

d. Coulomb’s law

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  India Study Solution - Test Series Answers

electrostatics  

Hints and Solutions of Physics Electrostatics MCQ Test Series – Set 3 (Q. No.21–30)

https://www.indiastudysolution.com

Answer 21:b. Answer 22: d.

Answer 23: c

(Hint: Both the spheres can be charged equally. Because for metallic sphere either solid or hollow, the charge will raised on the sphere. Since, both spheres have same surface area, so they can hold equal maximum charge)

Answer 24: a. Answer 25: b. Answer 26: c.

Answer 27: d (Hint: As conductor has positive charge. So, there is deficiency of electrons).

Answer 28: a.

Answer 29: a

(Hint: As revolving charge is equivalent to a current,
So,

www.indiastudysolution.com - NEET and JEE preparation | Physics Guide with Hints and Solutions | Electrostatics
 Answer 30: d.

 Electrostatics: Further study


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The new National Education Policy 2020 (NEP 2020) at a glance

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 13-Sept-2020

National Education Policy 2020 (NEP 2020) - A Brief Outline

The National Education Policy 2020 (NEP 2020), a draft of which was approved by the Union Cabinet of India on 29 July 2020, replaces the National Policy on Education of 1986.

EduNews @ www.indiastudysolution.com

The new National Education Policy 2020 (NEP 2020) outlines the vision of India's new education system. The new policy replaces the previous National Policy on Education, 1986. The NEP 2020 envisages transforming India's education system by 2030.

The Policy envisages a new curricular and pedagogical structure for school education that is responsive and relevant to the needs and interests of learners at different stages of their development. National Education Policy 2020 aims to shape an education system that benefits all of India's children. Prime Minister Shri Narendra Modi is hopeful that the new NEP 2020 will increase thirst for knowledge in schools and help in removing pressure on mark sheets for students.

Why National Education Policy

Policies are important because they help a school establish rules and procedures and create standards of quality for learning and safety, as well as expectations and accountability. Without these, schools, colleges, universities would lack the structure and academic guideline. The National Education Policy would help to function and provide the necessary educational needs of students.

For the first time the Government of India framed a National Policy on Education in 1986 which was later modified in 1992. Its major objective was to provide education to all sections of society, with a particular focus on scheduled castes, scheduled tribes, other backward classes and women, who were deprived of educational opportunities for centuries.

Changes in the new National Education Policy 2020 (NEP 2020)

Education Policy in India has been changed after a long period of 34 years. According to the National Education Policy 2020, Govt will phase out the affiliation of colleges in 15 years and a stage-wise mechanism will be established for granting graded autonomy to colleges. Under NEP 2020, there will be no rigid separations between arts and sciences, between curricular and extra-curricular activities, between vocational and academic streams.

The remarkable things about the New Education Policy 2020 are as follows:

5 YEARS FUNDAMENTALS

1. Nursery at 4 Years Old.

2. Junior KG at 5 Years Old.

3. Senior KG at 6 Years Old.

4. Class 1 at 7 Years Old.

5. Class 2 at 8 Years Old.

3 YEARS PREPARATORY

6. Class 3 at 9 Years Old.

7. Class 4 at 10 Years Old.

8. Class 5 at 11 Years Old.

3 YEARS MIDDLE

9. Class 6 at 12 Years Old.

10. Class 7 at 13 Years Old.

11. Class 8 at 14 Years Old.

4 YEARS SECONDARY

12. Class 9 at 15 Years Old.

13. Class 10 at 16 Years Old.

14. Class 11 at 17 Years Old.

15. Class 12 at 18 Years Old.

OTHER IMPORTANT CHANGES

  • There will be Board Exam in Class 12 only. Whereas earlier, it was mandatory to take Board Exams in Class 10, which will not happen now.
  • 4 Years of College Degree.
  • No more Class 10 Board Exam.
  • M.Phil Degree will be abolished.
  • Now students up to Class 5 will be taught in Mother Tongue, Local Language and National Language only. The rest of the subjects, even if they are English, will be taught as a subject.
  • Examinations will be done in the Semester form from Class 9 to 12 standard.
  • Schooling will be done under the 5 + 3 + 3 + 4 formula. (see table above).
  • College Degree will be of 3 and 4 years course.
  • Certificate will be given on the First year of Graduation, Diploma on the Second year and Degree in the Third year.
  • 3 Years Degree is for those students who do not have to take Higher Education. At the same time, students doing Higher Education will have to pursue 4 Years Degree.
  • Students pursuing 4 Years Degree will be able to do Master's Degree in one year. 
  • Now, students will not have to pursue M.Phil rather, MA students will now be able to pursue PhD directly.
  • Students will be able to do other courses in between.
  • Same rules will be applicable for all Government, Private and Deemed Institutions.

OTHER REFORMS UNDER NEW EDUCATION POLICY 2020

Gross enrollment ratio will be 50 percent by 2035 in Higher Education. At the same time, under the new Education Policy Rule 2020, if a student wants to pursue another course in the middle of a course, then, he/she can take a second course by taking a break for a limited time from the first course.

Many reforms have also been made in the Higher Education. Improvements include graded academic, administrative and financial autonomy etc.

Apart from this, the new National Education Policy Rule 2020 (NEP 2020) has recommended for e-courses to be started in Regional Languages. Virtual Laboratory will be developed. A National Educational Scientific Forum (NESF) will be started.

Our important Study Materials, Guide and Solutions (Absolutely Free)

EduNews: Centre increases NEET and JEE 2020 exam centres

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27-Aug-2020
JEE Main 2020 | JEE Advanced | NEET 2020
According to latest news update on NEET and JEE entrance exams, Ramesh Pokhriyal, Union Education Minister says the JEE exam centres have been increased to 660 from 570 while there are now 3,842 NEET centres, up from 2,546 for the convenience of students. Students have also been allotted exam centres of their choice.


Over 14 lakh admit cards for the medical and engineering entrance exams National Eligibility cum Entrance Test (NEET) and Joint Entrance Examination (JEE) have already been downloaded after the National Testing Agency (NTA) released them on Wednesday 19th Aug’20, even as the issue was discussed extensively during a meeting of chief ministers of non-Bharatiya Janata Party ruled states who decided to jointly move the Supreme Court to seek deferment of these exams.
(Source: Rediff edited)

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JEE Main 2020, NEET 2020, JEE Advanced exam dates: SC lawyer requests PMO for postponement

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19-Aug-2020
NTA JEE Main 2020 | JEE Advanced | NTA NEET 2020
According to a latest development, today one Supreme Court (SC) lawyer Alakh Alok Srivastava has submitted a request to the PMO seeking postponement of JEE Main 2020, JEE Advanced 2020 and NEET 2020 exam dates. All these exams are scheduled to be held in September 2020.

Srivastava said in his letter that the JEE and NEET examinations that will be held in September 2020 should be postponed. He added that if it is not possible to postpone it, then students who are unable to give these entrance exams in September must be given a chance to appear at a later stage.




Earlier on 17th August 2020, the honorable Supreme Court had dismissed pleas made by some parents to postpone JEE Main 2020 and NEET 2020 exams saying that postponement of JEE and NEET will put students' careers in peril. JEE Main 2020 is to be held online from September 1 to 6 while NEET 2020 for admission to undergraduate medical courses is slated to be held offline on September 13 across 161 exam centres in India.
Approximately 1 million students appear JEE Main examinations every year and even this year about 9,35,000 students have registered for JEE Main 2020 while close to 1.5 million students register every year for NEET to seek admission into undergraduate courses at medical colleges. This may be mentioned here that only about 12,000 seats are available across IITs whereas, only 50,000 odd seats are available for MBBS.
(Source: MoneyControl)

JEE Main 2020 Admit Card released: Download Hall Ticket from NTA JEE official site

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19-Aug-20
JEE Main 2020 Admit Card (Hall Ticket)

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The admit card for the Joint Entrance Examination (JEE) 2020 Main has been released by National Testing Agency (NTA) on 17th Aug, 2020. The candidates can download their hall ticket through official websites - nta.ac.in, jeemain.nta.nic.in. JEE Main examinations are scheduled to be held from September 1 to September 6, 2020 across the country.
Earlier, the Supreme Court had given the verdict that the JEE examination would not be postponed. The examination will be conducted in two shifts.
Latest update 19-Aug-2020 
Candidates who will appear for the examination can download the admit card / hall ticket by following these simple steps given below.
How to download JEE Main 2020 Admit Card: 


  1. Visit the official site of NTA JEE Main by clicking on the link given below.
  2. Click on Download JEE Main 2020 Admit Card available on the home page.
  3. A new page will open where candidates will have to enter the login credentials.
  4. Your admit card will be displayed on the screen.
  5. Check the admit card and click on download button there.
  6. Keep a hard copy of the same for further need.
The JEE Main hall ticket will carry details of the exam venue, time slot etc. The three-hour exam will be conducted online for both paper - I for admission to engineering courses and paper - II for admission to architecture courses. This year, a different paper for B Plan will also be conducted. There will be two shifts, morning shift will begin at 9:30 am and the afternoon shift will begin at 2:30 pm.
India Study Solution  wishes BEST of LUCK to its readers and all prospective candidates.

Free preparation Medical and Engineering Entrance Exams | Thermo chemistry (Thermodynamics)

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THERMODYNAMICS | THERMO CHEMISTRY

India Study Solution Test Series (Chemistry Objective Questions)

NEET, JEE IIT, AIIMS, NTSE | Engineering, BDS, MBBS Admission Test
Hi Guys,
Welcome back to your own site India Study Solution dedicated to engineering and medical aspirants.
https://www.indiastudysolution.com/2020/07/free-online-preparation-medical-and-engineering-entrance-exams-thermo-chemistry-s4.html
As you are aware that in each set of India Study Solution test series we bring for you 10 new most important expected questions with their hints & solutions.
Each set is a combination of typically important some basic with some advanced level questions structured to enhance your confidence while preparing for NEET, JEE, COMEDK and any other Admission Tests, NTSE etc.
Many coaching institutes in India are charging thousands of rupees whereas you can get the same benefit on this site sitting at the comfort of your home totally  Free .
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Chemistry Practice Questions: Thermodynamics (Thermo-chemistry)
India Study Solution MCQ Test Series – Set 4 (Q. No 31-40)
Question 31: Which of the following is an endothermic reaction?
a. N
b. N
c. H
d. C

Question 32: An ideal gas is taken around the cycle ABCA as shown in P-V diagram. The net work done by the gas during the cycle is equal to:
India Study Solution - Thermodynamics Test Series
a. 12P1V1
b. 6P
c. 5P
d. P

Question 33: Which of the following is correct option for free expansion of an ideal gas under adiabatic condition?
a. q = 0, ∆T < 0, w ≠ 0
b. q = 0, ∆T ≠ 0, w = 0
c. q ≠ 0, ∆T = 0, w = 0
d. q = 0, ∆T = 0, w = 0

Question 34: The energy associated with a system by virtue of its position is
a. Gibbs Energy
b. Internal Energy
c. Kinetic Energy
d. Potential Energy

Question 35: For isothermal expansion in case of an ideal gas:
a. ∆G = ∆S
b. ∆G = ∆H
c. ∆G = -T.∆S
d. None of these 

Question 36: One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 litre to 10 litres. The ∆E for this process is (R = 2 cal. mol
a. 1381.1 cal
b. Zero
c. 163. 7 cal
d. 9 L atm

Question 37: The difference between ∆H and ∆E on a molar basis for the combustion of Methane gas at T K (kelvin) would be:
a. Zero
b. - RT
c. -2RT
d. -3RT

Question 38: Which reaction, with the following values of ∆H, ∆S, at 400 K is spontaneous and endothermic?
a. ∆H = -48 kJ; ∆S = + 135 J/K
b. ∆H = -48 kJ; ∆S = -135 J/K
c. ∆H = + 48 kJ; ∆S = +135 J/K
d. ∆H = +48 kJ; ∆S = -135 J/K

Question 39: When a certain amount of ethylene was combusted, 6226 kJ heat was evolved. If heat of combustion of ethylene is 1411 kJ/mole, the volume of O
a. 296.5 ml
b. 296.5 litres
c. 6226 x 22.4 litres
d. 22.4 litres

Question 40: For the reaction
C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (l)
at constant temperature, ∆H – ∆E is
a. + RT
b. -3RT
c. +3RT
d. -RT
>>>>> <<<<<
India Study Solution MCQ Test Series - Hints and Solutions
tHERMODYNAMICS (THERMO-CHEMISTRY)
Set 4 (Q. No.31–40) Answers
Answer 31: b. Answer 32: c. Answer 33: d. Answer 34: d. Answer 35: c. Answer 36: b. Answer 37: c. Answer 38: c. Answer 39: b. Answer 40: b.

THERMODYNAMICS (Thermo-chemistry) - More India Study Solution Chemistry Test Series Questions

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EduNews: Board performance will not be considered for admissions by IITs this year

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20-July-2020

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The Human Resource Development Ministry on Friday announced relaxation in the admission to Indian Institutes of Technology (IITs) this year by not considering Class XII board performance.
“For admissions to IITs, apart from qualifying the JEE (Advanced), the eligibility was to secure either minimum score of 75 per cent marks in class XII Board exams or rank among the top 20 percentile in their qualifying examinations,” said Ramesh Pokhriyal Nishank, Minister for Human Resource Development.




Due to the partial cancellation of class XII exams by several Boards, Joint Admission Board (JAB) has decided to relax the eligibility criterion for JEE (Advanced) 2020 qualified candidates this time, he added.
Qualified candidates who have passed class XII examinations will now be eligible for admissions irrespective of marks obtained in the board exams.
Meanwhile, the Central Board of Secondary Education on Monday announced the board results of Class XII.
(Source: The Hindu)