## Kinematics - India Study Solution Test Series | Physics objective questions answers

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*Welcome back to **'India Study Solution’ Physics MCQ Test Series Section, each Test Series** containing exclusively selected 10 most important questions with hints & solutions from the Physics Chapter ***KINEMATICS.**

**KINEMATICS.**

Here you get solved MCQ Test Series on

__Kinematics (syllabus included below after the answers__), Physics objective questions with solutions on Kinematics, confidence boosting practice questions with hints and answers for preparing NEET, AIPMT, JEE Main, Medical, Dental Entrance Exams, Engineering Entrance Exams; MBBS and Engineering Admission Tests, NTSE, KVPY and other competitive exams.
Physics Notes and Study Materials with Key Points to remember and important Formulae and more on Kinematics - Motion in a straight line, Uniform and Non-uniform acceleration, Relative velocity, Scalars and Vectors and all topics in syllabus (provided at the end of hints / solutions) will be published separately

*(link for which will be provided here)***Kinematics:**

**Physics Guide and Solution**

*MCQ Test Series – Set 2 (Q. No. 11-20)*

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Question 11: SI unit of velocity is -

a. m/s

b. m/s

^{2}
c. m

d. m

^{2}/s
Question 12: The acceleration of a train between two stations is shown in the figure below. The maximum speed of the train is -

a. 60 m/s

a. 60 m/s

b. 30 m/s

c. 120 m/s

d. 90 m/s

Question 13: A particle moves a distance

*x*in time*t*according to equation*x = (t + 5)*^{–1}*The acceleration of particle is proportional to -*
a. (velocity)

^{2/3}
b. (velocity)

^{3/2}
c. (distance)

^{2}
d. (distance)

^{–2}
Question 14: Which of the following quantities can never be negative?

a. acceleration

b. displacement

c. distance travelled

d. work

Question 15: Acceleration-Time graph for a particle moving in a straight line is as shown in figure. Change in velocity of the particle from t= 0 to t = 6s is:

a. 10 m/s

a. 10 m/s

b. 4 m/s

c. 12 m/s

d. 8 m/s

Question 16: The displacement - time graph of a moving object is a straight line. Then -

a. its acceleration may be uniform

b. its velocity may be uniform

c. its acceleration may be variable

d. both its velocity and acceleration may be uniform

Question 17: If the velocity of an object is increasing and changing at a uniform rate then the acceleration of the object is -

a. positive

b. zero

c. negative

d. same as velocity

Question 18: A body dropped from the top of a tower covers a distance

*7x*in the last second of its journey, where*x*is the distance covered in the first second. How much time does it take to reach the ground?
a. 3 s

b. 4 s

c. 5 s

d. 6 s

Question 19: A stone falls freely under gravity. The total distance covered by in the last second of its journey is equal to the distance covered by it in first 3 s of its motion. The time for which the stone remains in air is -

a. 5 s

b. 12 s

c. 15 s

d. 8 s

Question 20: The acceleration of a moving object can be found from -

a. area under displacement-time graph

b. slope of displacement-time graph

c. area under velocity-time graph

d. slope of velocity-time graph

**Physics Guide and Solution: KINEMATICS**

__Solutions of Multiple Choice Questions MCQ Test Series – Set 2 (Q. No.11 –20__

*)*__Answer__11: a.

__Answer__12: b.

__Answer__13: b.

__Answer__14: c.

__Answer__15: b. (

__Hint__: Change in velocity = Net area under acceleration-time graph.)

__Answer__16: b.

__Answer__17: a.

__Answer__20: d.

__Kinematics Syllabus for JEE Main and NEET__**:**

*Frame of reference, Motion in a straight line, Uniform and Non-uniform motion, Average speed and instantaneous velocity, Uniformly accelerated motion, Velocity - Time, Position - Time graphs, Relations for uniformly accelerated motion, Relative velocity, Motion in a plane.*

*Scalars and Vectors, Vector addition and subtraction, Zero vector, Scalar and vector products, Unit vector, Resolution of a vector, Position and Displacement vector, General vector and notation, Equality of vector, Multiplication of vector and a real number.*