NTA NEET 2020, JEE Main and JEE Advanced 2020 exam schedules announced

5-May-2020
In continuation to our previous EduNews we let you know further that today our Human Resource Development (HRD) Minister announced the dates for JEE Main 2020 and NEET 2020 exams.

Nationwide Engineering Joint Exam JEE Main 2020 will now be held from July 18 to July 23 while medical entrance test NEET 2020 will be conducted on July 26. JEE Advanced 2020 is expected to be held in August 2020, dates of which are not decided yet.

Another important thing he mentioned that JEE Main 2021 and NEET 2021 are likely to be held on the reduced syllabus. The minister urged students to self-study with the help of online study materials (websites) to prepare for Medical and Engineering Entrance Exams. With low-connectivity areas, the content will be telecast through SWAYAM Prabha TV, he informed.

Over 9 lakh students have registered to appear for JEE Main 2020 and over 15.93 lakh have applied for NEET 2020, as per the National Testing Agency (NTA) – the exam conducting body.

The dates for JEE Advanced will be decided soon, said HRD minister Ramesh Pokhriyal through a webinar on 5the May’20 Tuesday. Only the top 2.5 lakh of JEE Main are eligible to appear for JEE Advanced.

While JEE Main 2020 and NEET 2020 were to be held in April and the first week of May, respectively which were then postponed to be held by May-end. JEE Advanced 2020 was to be held in 3^rd week of May. See latest update and new dates : 

• NEET and JEE 2020 latest updates - New Exam Dates announced by NTA
• 45 lakh candidates stuck as JEE, NEET other major Entrance Tests deferred due to Nation-wide lockdown amid Corona Virus outbreak  

45 lakh candidates stuck as JEE, NEET other major Entrance Tests deferred due to Nation-wide lockdown amid Corona Virus outbreak

As many as 45 lakh students preparing for major competitive examinations scheduled over the next three months are stranded as the nationwide lockdown in the wake of corona virus outbreak has upset the examination calendar by at least a month.

JEE Advanced, JEE Main, NEET, UGC-NET, CSIR UGC-NET, Indian Council of Agricultural Research (ICAR) scheduled in April, May and June 2020 will be affected by this lockdown.

Indian Government, NTA has notified that JEE and NEET Entrance Tests have been postponed to the last week of May keeping in mind the three week National lockdown due to Corona virus outbreak in India.

The National Eligibility cum Entrance Test (NEET) whose marks are used for admission in Medical Colleges across the country was scheduled to be held on 3rd May. As of now NEET is proposed to be held in the last week of May’20, exact dates will be announced later after assessing the situation due to corona virus pandemic.

Similarly the Engineering Entrance Test JEE Main has been postponed till last week of may as per the official statement issued yesterday 27^th March’20 in view of the current situation prevailing in the country due to Corona virus outbreak. The exam conducting agency NTA (National Testing Agency) has released a notification in which it has intimated to candidates that the examination dates will be announced letter after assessing the situation.

NEET is held annually for admission to undergraduate medical courses MBBS, BDS and Ayush programs through this examination. Admission to veterinary courses are also done on the basis of NEET score.

JEE main is held for admission to undergraduate engineering programs at NITs, IITs, other centrally funded technical institutions, cftri Institutions funded by participating State Governments. The exam is held twice a year and candidates are allowed to appear for both these examinations.

As of now, both NEET and JEE have been postponed till further dates are announced by NTA. These examinations were scheduled to be held in April and May 2020. NTA is yet to announce about other examinations.

JEE Main 2020 Registration started on jeemain.nic.in - Details and Guidelines - How to Apply

Joint Entrance Examination Main - JEE Main 2020 Registration will start shortly on jeemain.nic.in. Relax… here we have given step by step instructions of how to apply online for NTA JEE Main 2020 January Exam, syllabus, eligibility criteria and more.

JEE Main 2020 Registration: 

Joint Entrance Examination, JEE Main 2020 registration for January 2020 examination will start anytime today, September 3, 2019 on jeemain.nic.in. Students interested in taking up engineering courses in IITs, NITs, IIITs and other GFTIs are required to appear for JEE Main 2020 examination.

IIT and other engineering aspirants must be aware that the JEE Main 2020 exam pattern has been revised by National Testing Agency (NTA). As per NTA, the number of questions and their pattern has been revised (see the changes and syllabus as released by NTA by clicking on the link here).

JEE Main 2020 Eligibility:

Students studying in their Class 12 or who have completed their class 12 examinations in Physics, Chemistry, Mathematics and two other subjects are eligible to apply for JEE Main 2020. Please note, students who completed their Class 12 or any other qualifying examination in 2018, 2019 or the ones who would be appearing in 2020 are only eligible for JEE Main 2020 (link given hereunder for list of such exams).

Students who qualified in 2017 are not eligible to appear for JEE Main 2020.

Also, for JEE Main 2020 Paper II, students are required to have qualified in Physics, Chemistry and Mathematics. Instead of the 5 subject rule, the four subject rule is applicable for JEE Main 2020.

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JEE Main 2020 Syllabus:

As per the official website jeemain.nic.in, JEE Main 2020 syllabus is almost same as in Class 11 and Class 12 curriculum for Physics, Chemistry and Mathematics. Here is

JEE Main 2020 Syllabus is for quick reference.

JEE Main 2020 Important Dates:

• Online JEE Main 2020 Registration begins: September 3, 2019
• Last date to apply online: September 30, 2019
• Download of JEE Main 2020 Admit Card: From December 16, 2019
• Exam Dates: between January 6 to January 11, 2020 (will be confirmed by NTA later)

Joint Entrance Examination 2020 (Main) aspirants to note that

• Students who are eligible can apply for either / both of the two examinations which would be conducted by NTA. Only the better of the two scores would be considered for final merit list and rank calculation which would be released after JEE Main 2020 II paper result in April, 2020.
• JEE Main 2020 examination to be held in January’20 would be conducted only in Computer Based Test or CBT format. The Paper II, however, would be a pen and paper based test as was the earlier pattern.
• Students are advised to fill the online application forms at the earliest so that he / she can be allotted exam center as per his / her choice.
• The eligibility age limit would be calculated bases the April 2020 examination and there is no upper age limit.
• Students who have qualified the Class 12 or equivalent examination in 2017 or before are not eligible for JEE Main 2020 (Neither January nor April examinations).

JEE Main 2020 - How to Apply Online:

Candidates interested are required to fill the online application form on jeemain.nic.in, once it is released. NTA has released a step by step document on how to fill JEE Main 2020.

The 4 steps to apply are –

1. Registration,
2. Filling online application,
3. Uploading scanned images etc. and
4. Paying the application fees.

To download or check complete information about the Mode of Exam & Questions Pattern, Schedule for Exam & Result, State Eligibility, List and Year of Appearance in Qualifying Exams, Categories with Reservations percentages, NTA JEE (Main) 2020 Application Fees, Details regarding admission to NITs, IIITs, CFTIs, SFIs, State Engineering Colleges for Participating States and other Participating Engineering Colleges / Institutions, click on the link below -    

JEE Main 2020 Complete Official Information

 EduNews 
NEET Counselling 2019: Medical Council Committee released list of eligible candidates to fill in the vacant MBBS seats 

EduNews: JEE Main 2019 by NTA - Online Registration, Eligibility, Exam Date, Pattern, Admit card, Results and Preparation

What are JEE Main and JEE Advanced

JEE or Joint Entrance Examination is a national level engineering entrance exam for getting admissions into engineering colleges across India. Till 2011, All India Engineering Entrance Examination (AIEEE) used to be conducted by CBSE every year. In the year 2012, CBSE announced the replacement of IIT JEE and AIEEE with Joint Entrance Examination (JEE). The AIEEE was replaced by JEE Main to facilitate admissions in 31 NITs, 20 IIITs and 18 other CFTIs (Centrally Funded Technical Institutes) while IIT JEE was replaced by JEE Advanced to facilitate admissions in the 23 IITs (Indian Institute of Technology) and ISM Dhanbad. From 2019 instead of CBSE, JEE Main will be conducted twice a year in the month of January and April respectively by National Testing Agency (NTA). If a candidate achieves a certain cut-off score which is decided every year, in JEE Main then he or she qualifies for JEE Advanced. Qualification in JEE Main is not the only criteria for selection as the candidate should have secured at least 75 per cent marks in the 12th class examination, or be in the top 20 percentile in the 12th class examination conducted by the respective Boards. For SC/ST candidates the qualifying marks would be 65 per cent in the 12th class examination.

National Test Agency (NTA) has released the notification for Joint Entrance Examination, JEE Main 2019. Students interested in applying for admissions to undergraduate B.Tech, BE and B.Arch courses are required to fill the JEE Main 2019 online application.

Eligibility for NTA JEE Main 2019

For BE/B.Tech: The student must have passed 10+2 examination with Physics and Mathematics as compulsory subjects along with Chemistry/Biotechnology/Biology/ Technical Vocational subject.

For B.Arch/B.Planning: The student must have passed 10+2 with Mathematics as one of the subjects.

Age Criteria: General category candidates – born on or after 1st of October 1994. SC, ST, and PwD category candidates – born on or after 1st of October 1989.

See the Official Advertisementof NTA JEE Main 2019

To know more about Online Registration, Eligibility, Exam Date, Pattern, Admit card, Results and Preparation, Syllabus of NTA JEE Main 2019 please visit official website of NTA (National Testing Agency) https://www.nta.ac.in

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• NEET2019 and JEE Mains 2019 complete schedules released by NTA - National TestingAgency

NEET 2019 and JEE Mains 2019 complete schedules released by NTA - National Testing Agency

NTA (National Testing Agency) has released the Exam Dates, Registration, Modes of Exam and other details for NEET 2019, JEE Main I and II 2019.

The revised schedule for NTA NEET 2019 and NTA JEE Mains were released on 21^st August, 2018 by MHRD. Dates of registration, releasing admit card, exam date, modes of exam (format), results etc. of NEET 2019 and JEE Main 2019 are provided in the table below.

MHRD has decided against conducting the NEET 2019 examination twice next year. As per the earlier announcement by MHRD, NEET 2019 and JEE Main 2019 were to be conducted by NTA twice a year which has been changed now. Following a recommendation from Health Ministry, MHRD has scrapped the plan to conduct the examination in computer based format and twice a year. Now, NEET 2019 would be conducted on May 5, 2019 and the online application forms would begin from November 30, 2018. The results would be announced on June 5, 2019.

The forms for NTA JEE Main 2019 I would be released and begin from 1^st September, 2019. There would be no change in the proposal of conducting NTA JEE Main 2019 in online format only. The examination would be conducted in multiple sessions from January 6, 2019 to January 20, 2019 and students would have the option of appearing on any of the days by slot booking and NTA JEE Main II 2019 would be conducted in April’19. 

To apply online for JEE Main 2019 click JEE Main 2019 by NTA - Online Registration, Eligibility, Exam Date, Pattern, Admit card, Results and Preparation 

NTA NEET 2019: New Rules and Changes

1. The only change for NEET 2019 is that the conducting authority has been changed. Till 2018, NEET for undergraduate medical and dental admissions i.e. NEET-UG was conducted by CBSE.

2. From 2019 onwards, the examination would be conducted by NTA. Candidates would be required to fill the online application forms on nta.ac.in. Details of how to apply for NEET NTA 2019 would be released when the forms are released on November 30.

Everything else for NEET NTA 2019 remains unchanged. For example:

1. NTA NEET 2019 examination would be a pen and paper test.

2. NTA NEET 2019 syllabus would remain the same as was the case for 2018.

3. NTA NEET 2019 eligibility is expected to remain the same.

4. As earlier, it will be conducted only once a year, which would be on May 5, 2019. 

5. NTA NEET 2019 would be conducted in all the 8 regional languages as well as in English, Hindi and Urdu.

For more details and registrations please visit official website of NTA (National Testing Agency) https://www.nta.ac.in

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Circular and Rotational Motions - MCQ Test Series solved questions for NEET-UG, IIT JEE, COMEDK, MBBS and BDS admission tests, Engineering Entrance Exams

Physics: Circular Motion, Rotational Motion

Physics MCQ Test Series solved questions for NEET-ug, IIT JEE, COMEDK, MBBS and BDS admission tests, Engineering Entrance Exams and other such competitive exams.

Syllabus for NEET and IIT JEE:

Kinematics of Circular Motion; Dynamics of Uniform Circular Motion; Centripetal Force; Examples: vehicle on level circular road, vehicle on baked track; Angular Velocity and is relation with Linear Velocity; Torque or Moment of Force and Angular Momentum; Laws of Conservation of Angular Momentum; Theorems of perpendicular axes and parallel axes; Kinematics of Rotational Motion about a fixed axis; Rolling Motion; General relation among Position-Velocity-Acceleration for Motion in a plane and Uniform Circular Motion; Centrifugal Force; Motion in a vertical circle; Rotational Motion of a rigid body; Moment of Inertia; Angular Impulse.

India Study Solution

Solved MCQ Test Series – Set 3 (Q. No. 21-30)

Question 21: The angular speed of a fly wheel making 120 rev/min is:

a. 2π rad/s

b. 4π² rad/s

c. π rad/s

d. 4π rad/s

Question 22: A child is swinging a swing, minimum and maximum heights of swing from earth’s surface are 0.75 m and 2 m respectively. The maximum velocity of this swing is –

a. 5 m/s

b. 10 m/s

c. 15 m/s

d. 20 m/s

Question 23: An aeroplane is flying with a uniform speed of 100 m/s along a circular path of radius 100 m. The angular speed of the aeroplane will be:

a. 1 rad/s

b. 2 rad/s

c. 3 rad/s

d. 4 rad/s

Question 24: A block of mass m slides down along the surface of the bowl from the rim to the bottom as shown in fig. The velocity of the block at the bottom will be –

Question 25: When a body moves with a constant speed along a circle:

a. Its velocity remains constant

b. No force acts on it

c. No work is done on it

d. No acceleration is produced on it

Question 26: A 1 kg ball is rotated in a vertical circle by using a string of length 0.1 m. If the tension in the string at the lowest point is 29.4 N, its angular velocity at that position is –

a. 7 rads^-1

b. 14 rads^-1

c. 3.5 rads^-1

d. 25.6 rads^-1

Question 27: A cyclist moves in a circular track of radius 100 m. If the coefficient of friction is 0.2. Then the maximum speed with which the cyclist take a turn without leaning inwards is:

a. 14.0 m/s

b. 140 m/s

c. 1.4 m/s

d. 9.8 m/s

Question 28: If all objects on the equator of earth feel weightless then the duration of the day will nearly become –

a. 6.2 hr

b. 4.4 hr

c. 2.2 hr

d. 1.41 hr

Question 29: Two racing cars of masses m₁ and m₂ are moving in circles of radii r₁ and r₂ respectively. Their speeds are such that each makes a complete circle in the same time t. The ratio of the angular speeds of the first to the second car is:

a. 1: 1

b. m₁: m₂

c. r₁: r₂

d. m₁m₂: r₁r₂

Question 30: A 2 kg stone is swung in a vertical circle by attaching it at the end of a string of length 2m. If the string can withstand a tension 140.6 N, the maximum speed with which the stone can be rotated is –

a. 22 ms^-1

b. 44 ms^-1

c. 33 ms^-1

d. 11 ms^-1

Download Hints / Answers

 Circular and Rotational Motions - More Questions Answers  

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